Bennabooidn
Answered

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ba^4•(2ba^4)^-3
The answer key says 1/8b^2a^8 but I don't understand how they got that.

Sagot :

Konrad509idn
[tex]ba^4\cdot(2ba^4)^{-3}=\dfrac{ba^4}{(2ba^4)^3}=\dfrac{ba^4}{8b^3a^{12}}=\dfrac{1}{8b^2a^8}[/tex]
Panoyinidn
[tex]a^{4}b(2ab^{4})^{-3} [/tex]

[tex]a^{4}b( \frac{1}{(2a^{4}b)^{3}})[/tex]

[tex]a^{4}b( \frac{1}{(2a^{4}b)(2a^{4}b)(2a^{4}b)}) [/tex]

[tex]a^{4}b( \frac{1}{8a^{12}b^{3}}) [/tex]

[tex] \frac{1}{8a^{8}b^{2}} [/tex]


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