Get detailed and accurate responses to your questions on IDNLearn.com. Get the information you need from our community of experts who provide accurate and thorough answers to all your questions.
Sagot :
so 9x^2+12x+4=0
so the quadratic formulat is (-b+/-(squrt(b^2-4ac)))/(2a)=x
subsitute
ax^2+bx+c=
9=a
12=b
4=c
(-12+/-(squrt(12^2-4(9)(4))))/(2(9))=x
(-12+/-(squrt(144^2-144)))/18)=x
(-12+/-0)/18)=x
-12/18=x
-2/3=x
so the quadratic formulat is (-b+/-(squrt(b^2-4ac)))/(2a)=x
subsitute
ax^2+bx+c=
9=a
12=b
4=c
(-12+/-(squrt(12^2-4(9)(4))))/(2(9))=x
(-12+/-(squrt(144^2-144)))/18)=x
(-12+/-0)/18)=x
-12/18=x
-2/3=x
[tex] Discriminant= b^{2}-4.a.c \\ \\ We\:need\:to:-b+ \sqrt{discriminant} /2a \\ \\ 9x^{2} +12x+4=0 \\ => 12^{2} -4.9.4 \\ 144-144=0 \\ \sqrt{0} =0 \\ \\ -12+ 0/18= \frac{-12}{18} = \frac{-2}{3} \\ \\ That`s\: enough=>x= \frac{-2}{3} \\ \\ \framebox[1.1\width]{Good Luck!} \par[/tex]
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.