Answered

IDNLearn.com provides a comprehensive platform for finding accurate answers. Find in-depth and trustworthy answers to all your questions from our experienced community members.

the perimeter of a rectangle is 66 cm and its width is half its length. what are the length and the width of the rectangle?

Sagot :

IGreenidn
P = 2(l + w)

w = l/2

Plug in 'l/2' for 'w' in the equation with '66':

66 = 2(l + l/2)

66 = 2l + 2l/2

66 = 2l + l

66 = 3l

22 = l

So the length is 22.

Now plug this in to find the width.

66 = 2(22 + w)

66 = 44 + 2w

22 = 2w

11 = w

So the width is 11, and the length is 22.
Arnfrsidn
Let's set width = w

Then length = 2w

We can set up the equation:

[tex] 2(w+ 2w) = 66[/tex]

[tex] 2(3w) = 66[/tex]

[tex] 6w = 66[/tex]

[tex] w = \frac{66}{6} = \boxed{11}[/tex]

Then we plug in:

[tex]l = 2w = 2(11) = \boxed{22}[/tex]

Hope this helps :)

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.