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solve the system using elimination. 3x+2y=17, 2x+5y=26

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[tex]3x+2y=17 \ \ \ |\times (-2) \\ 2x+5y=26 \ \ \ |\times 3 \\ \\ -6x-4y=-34 \\ \underline{6x+15y=78 \ \ \ \ \ } \\ 15y-4y=78-34 \\ 11y=44 \ \ \ |\div 11 \\ y=4 \\ \\ 3x+2y=17 \\ 3x+2 \times 4=17 \\ 3x+8=17 \ \ \ |-8 \\ 3x=9 \ \ \ |\div 3 \\ x=3 \\ \\ \boxed{(x,y)=(3,4)}[/tex]
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