AnneOfNarniaidn
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Two dice are rolled. What is the probability that the sum of the numbers rolled is
a) not less than 7?
b) not more than 7?

Sagot :

Konrad509idn
[tex]P(A)=\dfrac{|A|}{|\Omega|}\\\\ |\Omega|={6+2-1\choose 2}={7\choose 2}=\dfrac{7!}{2!5!}=\dfrac{6\cdot7}{2}=21\\\\ a)\\ A=\{(1,6),(2,6),(3,6),(4,6),(5,6),(6,6),(2,5),(3,5),(4,5),(5,5),\\ (3,4),(4,4)\}\\ |A|=12\\ P(A)=\dfrac{12}{21}=\dfrac{4}{7}\\\\ b)\\ A=\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,2),(2,3),(2,4),(2,5),\\ (3,3),(3,4)\}\\ |A|=12\\ P(A)=\dfrac{12}{21}=\dfrac{4}{7}[/tex]
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