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Sagot :
If Luis had a smaller pizza with a diameter of 5 inches, and Marty ate a larger pizza with a diameter of 15 inches, Marty would eat more than Luis.
First, we can find the areas of the pizzas.
Luis's:
[tex]\sf~A=\pi\!\!~r^2[/tex]
Plug in what we know and simplify:
[tex]\sf~A=(3.14)(5)^2[/tex]
[tex]\sf~A=(3.14)(25)[/tex]
[tex]\sf~A=(78.5)[/tex]
Divide by 6 to see how big each slice is.
[tex]\sf78.5\div6\approx13.08[/tex]
Multiply by 5 to find out how much pizza Luis ate total:
[tex]\sf13.08\times5=65.4[/tex]
So Luis ate approximately 65.4 square inches of pizza.
Now let's find out how much Marty ate.
[tex]\sf~A=\pi\!\!~r^2[/tex]
Plug in what we know and simplify:
[tex]\sf~A=(3.14)(15)^2[/tex]
[tex]\sf~A=(3.14)(225)[/tex]
[tex]\sf~A=(706.5)[/tex]
Divide by 6 to see how big each slice is.
[tex]\sf78.5\div6=117.75[/tex]
Multiply by 5 to find out how much pizza Marty ate total:
[tex]\sf117.75\times5=588.75[/tex]
So Marty ate 588.75 square inches of pizza, which is more than what Luis ate, 65.4 square inches.
First, we can find the areas of the pizzas.
Luis's:
[tex]\sf~A=\pi\!\!~r^2[/tex]
Plug in what we know and simplify:
[tex]\sf~A=(3.14)(5)^2[/tex]
[tex]\sf~A=(3.14)(25)[/tex]
[tex]\sf~A=(78.5)[/tex]
Divide by 6 to see how big each slice is.
[tex]\sf78.5\div6\approx13.08[/tex]
Multiply by 5 to find out how much pizza Luis ate total:
[tex]\sf13.08\times5=65.4[/tex]
So Luis ate approximately 65.4 square inches of pizza.
Now let's find out how much Marty ate.
[tex]\sf~A=\pi\!\!~r^2[/tex]
Plug in what we know and simplify:
[tex]\sf~A=(3.14)(15)^2[/tex]
[tex]\sf~A=(3.14)(225)[/tex]
[tex]\sf~A=(706.5)[/tex]
Divide by 6 to see how big each slice is.
[tex]\sf78.5\div6=117.75[/tex]
Multiply by 5 to find out how much pizza Marty ate total:
[tex]\sf117.75\times5=588.75[/tex]
So Marty ate 588.75 square inches of pizza, which is more than what Luis ate, 65.4 square inches.
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