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find the slope of a line containing points (-2,8) and (5,3).

Sagot :

[tex] \frac{3-8}{5--2}= \frac{-5}{7} [/tex]

Slope: [tex]- \frac{5}{7} [/tex]
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}\\\\ m=\dfrac{8-3}{-2-5}\\ m=\dfrac{5}{-7}\\ m=-\dfrac{5}{7}\\[/tex]