IDNLearn.com offers a seamless experience for finding and sharing knowledge. Discover comprehensive answers to your questions from our community of knowledgeable experts.
Sagot :
By Newton's law of gravitation
[tex]F= \frac{Gm_{1}m_{2}}{r^2} [/tex]
then for [tex]m_{1}=m_{2}=m[/tex]
[tex]r=sqrt{\frac{Gm^2}{F}}[/tex]
therefore
r=0.849m (3sf)
[tex]F= \frac{Gm_{1}m_{2}}{r^2} [/tex]
then for [tex]m_{1}=m_{2}=m[/tex]
[tex]r=sqrt{\frac{Gm^2}{F}}[/tex]
therefore
r=0.849m (3sf)
Answer:
d = 0.84 meters
Explanation:
It is given that,
Mass of two objects, [tex]m_1=m_2=2\times 10^2\ kg[/tex]
Gravitational force between them, [tex]F=3.7\times 10^{-6}\ N[/tex]
The force that exist between two objects is called gravitational force. Its expression is given by :
[tex]F=G\dfrac{m_1m_2}{d^2}[/tex]
Where
d is the distance between two masses
[tex]d=\sqrt{\dfrac{Gm^2}{F}}[/tex]
[tex]d=\sqrt{\dfrac{6.67\times 10^{-11}\times (2\times 10^2)^2}{3.7\times 10^{-6}}}[/tex]
d = 0.84 meters
So, the distance between two masses is 0.84 meters. Hence, this is the required solution.
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.
