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Sagot :
By Newton's law of gravitation
[tex]F= \frac{Gm_{1}m_{2}}{r^2} [/tex]
then for [tex]m_{1}=m_{2}=m[/tex]
[tex]r=sqrt{\frac{Gm^2}{F}}[/tex]
therefore
r=0.849m (3sf)
[tex]F= \frac{Gm_{1}m_{2}}{r^2} [/tex]
then for [tex]m_{1}=m_{2}=m[/tex]
[tex]r=sqrt{\frac{Gm^2}{F}}[/tex]
therefore
r=0.849m (3sf)
Answer:
d = 0.84 meters
Explanation:
It is given that,
Mass of two objects, [tex]m_1=m_2=2\times 10^2\ kg[/tex]
Gravitational force between them, [tex]F=3.7\times 10^{-6}\ N[/tex]
The force that exist between two objects is called gravitational force. Its expression is given by :
[tex]F=G\dfrac{m_1m_2}{d^2}[/tex]
Where
d is the distance between two masses
[tex]d=\sqrt{\dfrac{Gm^2}{F}}[/tex]
[tex]d=\sqrt{\dfrac{6.67\times 10^{-11}\times (2\times 10^2)^2}{3.7\times 10^{-6}}}[/tex]
d = 0.84 meters
So, the distance between two masses is 0.84 meters. Hence, this is the required solution.
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