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Hippalectryonidn
The diagonal of a square is [tex]\sqrt{2}[/tex] times its side, hence its perimeter is [tex]4*24/\sqrt{2}\approx68[/tex]  feet
Konrad509idn
[tex]24=a\sqrt2\\ a=\dfrac{24}{\sqrt 2}\\ a=\dfrac{24\sqrt2}{ 2}\\ a=12\sqrt2\\\\ p=4a\\ p=4\cdot12\sqrt2\\ p=48\sqrt2\approx68[/tex]

68 ft
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