Ryleighhancockidn
Answered

Get expert insights and community-driven knowledge on IDNLearn.com. Our community is here to provide detailed and trustworthy answers to any questions you may have.

x-2y=16 and x-y=8 its a system of equation. I don't know how to do this please help.

Sagot :

[tex]\left\{\begin{array}{ccc}x-2y=16\\x-y=8\end{array}\right\\\\\#1\ elimination\ method:\\\left\{\begin{array}{ccc}x-2y=16\\x-y=8&|change\ signs\end{array}\right\\\underline{+\left\{\begin{array}{ccc}x-2y=16\\-x+y=-8\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ the\ equations\\.\ \ \ \ \ -y=8\to\boxed{y=-8}\\\\subtitute\ value\ of\ y=-8\ to\ the\ second\ equation\\\\x-(-8)=8\\x+8=8\ \ \ \ |subtract\ 8\ from\ both\ sides\\\boxed{x=0}\\\\Answer:\boxed{\boxed{\left\{\begin{array}{ccc}x=0\\y=-8\end{array}}}[/tex]

[tex]\#\ subtitute\ method:\\\left\{\begin{array}{ccc}x-2y=16\\x-y=8&|add\ "y"\ to\ both\ sides\end{array}\right\\\left\{\begin{array}{ccc}x-2y=16&(1)\\x=y+8&(2)\end{array}\right\\\\subtitute\ (2)\ to\ (1)\\\\(y+8)-2y=16\\y+8-2y=16\\-y+8=16\ \ \ \ |subtract\ 8\ from\ both\ sides\\-y=8\to \boxed{y=-8}\\\\subtitute\ value\ of\ y=-8\ to\ (2)\\x=-8+8\\\boxed{x=0}\\\\Answer:\boxed{\boxed{\left\{\begin{array}{ccc}x=0\\y=-8\end{array}\right}}[/tex]
Crisforpidn
x = 2y + 16 and x = 8 + y ;
2y + 16 = 8 + y ;
2y - y = 8 - 16 ;
y = - 8 ;
x = 8 + ( - 8 ) ;
x = 0;
checking ( 0 , - 8 ) ;
0 - 2 × ( - 8 ) = 16 ( correct !
0 - ( - 8 ) = 8 correct !

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.