Kmannidn
Answered

Join the IDNLearn.com community and start exploring a world of knowledge today. Our platform offers reliable and comprehensive answers to help you make informed decisions quickly and easily.

Two carts collide on a level, friction-less track. Cart A has a mass of 200 g and is initially stationary. Cart B has a mass of 100 g and is initially moving with a velocity of +2.0 m/s. After the collision between the carts, cart B has a velocity of -0.5 m/s.

Calculate the velocity of cart A after the collision.
(Use conservation of momentum, KE is not conserved.)

Sagot :

convert 200 grams and 100 grams to 2kg and 1kg respectively 
momentum = mass x velocity 
momentum = 1 x 2 
initial momentum = 2 kg m/s
second scenario, cart b is moving -.5 m/s
momentum = mass x velocity
momentum = 1 x -.5
final momentum = -.5 kg m/s

momentum has to be the same in both scenarios so the 2 kg truck has to have a momentum of 2.5 kg m/s to push the total momentum of the second scenario to be 2 kg m/s like the first scenario

2.5 = 2 x velocity

velocity of cart a after the collision = 1.25 m/s

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.