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x^2+4x=13 Solve by equations by completing the square. Please show all work

Sagot :

Panoyinidn
[tex]x^{2} + 4x = 13[/tex]
[tex]x^{2} + 4x - 13 = 13 - 13[/tex]
[tex]x^{2} + 4x - 13 = 0[/tex]
[tex]x = \frac{-4 +/- \sqrt{4^{2} - 4(1)(13)}}{2(1)} [/tex]

[tex]x = \frac{-4 +/- \sqrt{16 - 52}}{2} [/tex]

[tex]x = \frac{-4 +/- \sqrt{-36}}{2}[/tex]

[tex]x = \frac{-4 +/- \sqrt{36 * (-1)}}{2} [/tex]

[tex]x = \frac{-4 +/- \sqrt{36} \sqrt{-1}}{2} [/tex]

[tex]x = \frac{-4 +/- 6i}{2} [/tex]

[tex]x = \frac{-4 + 6i}{2} [/tex]          [tex]x = \frac{-4 - 6i}{2} [/tex]

[tex]x = -2 + 3i[/tex]      [tex]x = 2 - 3i[/tex]

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