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prove that the recurring decimal 0.39 = 13/33

Sagot :

Konrad509idn
[tex]x=0.\overline{39}\\100x=39.\overline{39}\\ 100x-x=39.\overline{39}-0.\overline{39}\\ 99x=39\\ x=\dfrac{39}{99}=\dfrac{13}{33} [/tex]
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