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Evaluate log (base 9) 27. Can someone explain this one for me so i could do some tasks on my own?

Sagot :

You would use some properties of the logarithm. First, [tex]log_927=log_{3^2}27=\frac{1}{2}log_327[/tex]. So, now you have [tex]log_327[/tex] to calculate. It's [tex]log_33^3=3[/tex], so the final result is [tex]\frac{1}{2}*3=\frac{3}{2}[/tex]
Hope it helps.
[tex]log_927=log_93^3=3log_93=3log_9\sqrt9=3log_99^\frac{1}{2}\\\\=\frac{1}{2}\cdot3log_99=\frac{3}{2}[/tex]