Answered

Get the information you need with the help of IDNLearn.com's expert community. Join our interactive community and access reliable, detailed answers from experienced professionals across a variety of topics.

find the zeros of the function h(x)=x^2-5x-50 by factoring

Sagot :

[tex]h(x)=x^2-5x-50=x^2-5x-25-25=x^2-25-5x-25\\\\=(x^2-25)-(5x+25)=(x^2-5^2)-5(x+5)\\\\=(x-5)\underline{(x+5)}-5\underline{(x+5)}=(x+5)(x-5-5)=(x+5)(x-10)\\\\Answer:Zeros\ are\ x=-5\ and\ x=10.[/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.