Talhahassan07idn
Answered

IDNLearn.com: Your trusted source for finding accurate and reliable answers. Get accurate and comprehensive answers from our network of experienced professionals.

The height in meters of a projectile is modeled the function h(t)= -5t^2+25, where t is the time in seconds. a) Find the point when the object hits the ground. b) Find the average rate of change from the point when the projectile is launched to the point in which it hits the ground. c) Estimate the object’s speed at the point of impact.

Sagot :

Since3122015idn
[tex]h(t)=-5t^2+25\\-5t^2+25=0\\25=5t^2\\5=t^2\\\sqrt{5}=t\\\\A(t)=\frac{f(t+h)-f(t)}{h}\\A(0)=\frac{f(\sqrt{5})-f(0)}{\sqrt{5}}\\A(0)=\frac{0+25}{\sqrt{5}}\\A(0)=\frac{25\sqrt{5}}{5}\\A(0)=5\sqrt{5}\\\\h'(t)=-10t\\h'(\sqrt{5})=-10(\sqrt{5})[/tex]

A. sqrt(5)
B. 5 sqrt(5)
C. 10 sqrt(5)
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.