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complete the equation for the linear function whose graph contains the point (-1,2) and has a slope of 0.9.
y=_____x + ______


Sagot :

Plug it into point-slope form.

y - y1 = m(x - x1)

Where y1 is the y-value of the point, x1 is the x-value, and 'm' is the slope.

So plug in -1 for x1, 2 for y1, and 0.9 for 'm':

y - 2 = 0.9(x + 1)

Simplify to get in slope-intercept form:

Distribute 0.9 into the parenthesis:

y - 2 = 0.9x + 0.9

Add 2 to both sides:

y = 0.9x + 2.9