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Sagot :
so first solve for for volume of grease held by tube
volume of cylinder=height times area of base
area of base=circle so
height times pi times radius^2
pi=aprox 3.14
height=14
radius=1.5
14 times 3.14 times 1.5^2=98.91 in^3 of grease
then divide
98.91/15=6.594
you can't squeeze the gun exactly 0.569 times so we round down and get
6
the answer is 6 times
volume of cylinder=height times area of base
area of base=circle so
height times pi times radius^2
pi=aprox 3.14
height=14
radius=1.5
14 times 3.14 times 1.5^2=98.91 in^3 of grease
then divide
98.91/15=6.594
you can't squeeze the gun exactly 0.569 times so we round down and get
6
the answer is 6 times
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