Lightfoote31idn
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What is the inverse function of g(x)=1/x-2

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Konrad509idn
Assuming it's [tex]g(x)=\dfrac{1}{x-2}[/tex]

[tex]y=\dfrac{1}{x-2}\\ x-2=\dfrac{1}{y}\\ x=\dfrac{1}{y}+2\\ g^{-1}(x)=\dfrac{1}{x}+2[/tex]
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