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Find the lateral area for the regular pyramid.

Find The Lateral Area For The Regular Pyramid class=

Sagot :

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2x2+2x[tex] \sqrt{(2/2) x^{2} +3 x^{2} } +2 x \sqrt{(2/2) x^{2} +3 x^{2} }[/tex]
The answer is about 16.649

Answer:

Lateral area of a regular pyramid with square is 12.64 square unit

Step-by-step explanation:

Given : A regular pyramid with base is a square.

We have to find the  lateral area for the regular pyramid.

Lateral area of a regular pyramid with square =  [tex]a\sqrt{a^2+4h^2}[/tex]

Where, a is side of square

and h is height of pyramid.

Substitute, a = 2

and h = 3

we have,

Lateral area of a regular pyramid with square =  [tex]2\sqrt{(2)^2+4(3)^2}[/tex]

Simplify, we have,

Lateral area of a regular pyramid with square = 12.64

Thus, The Lateral area of a regular pyramid with square is 12.64 square unit

                   

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Question

Find the lateral area for the regular pyramid.

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