Get detailed and reliable answers to your questions on IDNLearn.com. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.
Sagot :
mg = 6.2 x 9.81 = 60.822
This is also normal force.
Coefficient of friction times normal force is the force due to friction:
60.822 x 0.24 = 14.6N
F = MA so F(your force) - F(friction) = 6.2 x 0.5
= 3.1
Your answer is 3.1+ 14.6
I hope this is correct though I might be wrong.
Answer:
17.68 N
Explanation:
mass of block, m = 6.2 kg
acceleration, a = 0.5 m/s^2
coefficient of friction, μ = 0.24
Net force - mass x acceleration
F - f = ma
where, F is the pulling force, f is the friction force and a be the acceleration
F - μ mg = ma
F - 0.24 x 6.2 x 9.8 = 6.2 x 0.5
F - 14.58 = 3.1
F = 17.68 N
Thus, the pulling force is 17.68 N.
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.
