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Sagot :
mg = 6.2 x 9.81 = 60.822
This is also normal force.
Coefficient of friction times normal force is the force due to friction:
60.822 x 0.24 = 14.6N
F = MA so F(your force) - F(friction) = 6.2 x 0.5
= 3.1
Your answer is 3.1+ 14.6
I hope this is correct though I might be wrong.
Answer:
17.68 N
Explanation:
mass of block, m = 6.2 kg
acceleration, a = 0.5 m/s^2
coefficient of friction, μ = 0.24
Net force - mass x acceleration
F - f = ma
where, F is the pulling force, f is the friction force and a be the acceleration
F - μ mg = ma
F - 0.24 x 6.2 x 9.8 = 6.2 x 0.5
F - 14.58 = 3.1
F = 17.68 N
Thus, the pulling force is 17.68 N.
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