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solve y-2x=3 and 3x-2y=5 using substitution

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y - 2x = 3
3x - 2y = 5

y - 2x = 3

Add 2x to both sides:

y = 2x + 3

Plug in 2x + 3 for 'y' in the 2nd equation:

3x - 2(2x + 3) = 5

Distribute -2:

3x - 4x - 6 = 5

Combine like terms:

-x - 6 = 5

Add 6 to both sides:

-x = 11

Multiply -1 to both sides:

x = -11

Now plug this into any of the 2 equations to solve for 'y':

y - 2x = 3

y - 2(-11) = 3

Multiply:

y + 22 = 3

Subtract 22 to both sides:

y = -19

So the solution is (-11, -19)
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