Answered

Find solutions to your problems with the help of IDNLearn.com's knowledgeable users. Get accurate and detailed answers to your questions from our dedicated community members who are always ready to help.

Multiplying polynomials

(3x-8) (2x-2)

Sagot :

Panoyinidn
(3x - 8)(2x - 2)
(6x² - 6x - 16x + 16)
6x² - 22x + 16
Yvonnemnidn


When multiplying polynomials, use a process called FOIL

First

Outer

Inner

Last

(3x-8)(2x-2)

Multiply the two first numbers:

3x*2x=6x^2

Multiply the two outer numbers:

3x*-2=-6x

Multiply the two inner numbers:

-8*2x=-16x

Multiply the two last numbers:

-8*-2=16

Now add all your answers together:

6x^2-6x-16x+16

Simplify:

6x^2-22x+16

And there's your answer.


We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.