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find the length and width of a rectangle that has the given area and a maximum area. Perimeter: 80 meters
IF THIS IS FOR 40 WHAT IS IT FOR 80 For maximum area, you've got a square. So 10 x 10. Proof 2x + 2y = 40 x + y = 20 Max xy =Max x(20-x) = Max 20x - x^2 Take 1st derivative and set to zero 20 - 2x = 0 2x = 20 x = 10 So y = 10
The maximum area of a shape will always be a square. So, the sides will all be 20, because four of those add up to 80. Length and width will be 20. That would make the area 400 units².
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