Answered

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what is the result?

∫([1/x].dx/x^3)
D=[1/2, 1]

Sagot :

Hippalectryonidn
[tex]\displaystyle\int_{.5}^1\frac{1}x\frac{dx}{x^3}=\int_{.5}^1\frac{dx}{x^4}=\left[\frac{-1}{3x^3}\right]_{.5}^1=\frac{7}3[/tex]

[Your notation is not 100% clear since you're not using the math tool, so if that's not what you meant, leave a comment and I'll correct the answer.]
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