From science to arts, IDNLearn.com has the answers to all your questions. Our experts are available to provide accurate, comprehensive answers to help you make informed decisions about any topic or issue you encounter.

prove that x^n-Y^n divisible by x-y for all natural numbers x,y (x!=y),and n.

Sagot :

Let's do that by induction :
For [tex]n=1[/tex], [tex]x^1-y^1[/tex] is obviously divisible by [tex]x-y[/tex]

If we assume the property holds at rank [tex]n[/tex], then [tex]x^{n+1}-y^{n+1}=x(x^n-y^n)+y^n(x-y)[/tex]. Since [tex]x^n-y^n[/tex] is divisible by [tex](x-y)[/tex], we have [tex]A[/tex] such that [tex]x^n-y^n=A(x-y)[/tex]  hence [tex]x^{n+1}-y^{n+1}=(x-y)(Ax+y^n)[/tex].

Hence by induction for all [tex]n\ge1[/tex], [tex]x-y[/tex] divides [tex]x^n-y^n[/tex]