Tamic198223idn
Answered

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What is x^2+8x-5 in vertex form? Please explain.

Sagot :

Konrad509idn
[tex]x^2+8x-5=\\ x^2+2\cdot4\cdot x-5=\\ x^2+2\cdot4\cdot x+4^2-4^2-5=\\ (x+4)^2-16-5=\\ (x+4)^2-21 [/tex]
Mathgirl22idn
[tex]x^2+8x-5=\\ x^2-8x+16-21=\\ (x-4)^2-21[/tex]
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