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find the slope of the line that contains (1,6) and (10, -9).

Sagot :

m=[tex] \frac{y1-y2}{x1-x2} [/tex] = [tex] \frac{6-(-9)}{1-10}= \frac{15}{-9}=- \frac{5}{3} [/tex]
So,

To find the slope, simply subtract the given solutions and put them in the proper form.

10 - 1 = 9
-9 - 6 = -15

[tex]Slope = \frac{-15}{9} \ or\ \frac{-5}{3} \ or\ -\frac{5}{3} [/tex]