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ted is making three picture frames like the one shown below.what length wood does ted need for all three picture frames?

Ted Is Making Three Picture Frames Like The One Shown Belowwhat Length Wood Does Ted Need For All Three Picture Frames class=

Sagot :

Invader12idn
bear with me on this one. start out with 5(3/4)+7(7/8) to get two sides stated in the problem. i then made both an improper fraction, leaving 23/4+63/8 i multiplied them by 2 to get the perimeter. thus 2(23/4)+2(63/8)=23/2+63/4. i multiplied the first term by 1/2 to get them both over 4. 46/4+63/4=109/4. then divide 109 by 4 to get 81.75 which is 81 3/4.
So, Ted wants to make 3 frames. Two sides of each frame are 5 and 3/4 in. long. The other two sides are 7 and 7/8 in. long. Two times three is six, so he needs 6 of each length. I am going to change them into mixed numbers to make them easier to multiply with. So, what we have up to this point is this: (6)(23/4) + (6)(63/8)= 138/4 + 378/8= BTW, I am adding them because you are trying to find the total wood lenght. Anyway, so I can't add yet because one has a denominator of 4 and the other has 8. Can't add like that, so I will change it to this: 276/8 +378/8= 654/8= 81 and 3/4 as your final answer
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