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Sagot :
sonsecutive numbers is
first number=x
second=x+1
third=x+2 so
x+x+1+x+2=135 or add like terms
3x+3=135
subtract 3 from both sides
3x=132
divide by 3
x=44
firts number=44
next number=45
next number=46
numbers are 44,45,46
first number=x
second=x+1
third=x+2 so
x+x+1+x+2=135 or add like terms
3x+3=135
subtract 3 from both sides
3x=132
divide by 3
x=44
firts number=44
next number=45
next number=46
numbers are 44,45,46
Three consecutive integers can be represented as followed.
X → first integer
X + 1 → second integer
X + 2 → third integer
Since the sum of our three consecutive integers is 135, we can set up an equation to represent this.
X + X + 1 + X + 2 = 135
-Simplify on the left-
3x + 3 = 135
-3 -3
3x = 132
÷3 ÷3 ← divide both sides by 3
X = 44
X + 1 = 45
X + 2 = 46
Therefore, the three consecutive integers are 44, 45, and 46. The smallest number would be 44.
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