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x^2+x=2?? how would i solve this??

Sagot :

Belcatyaidn
x²+x=2
x²+x-2=0
x=[tex] \frac{-1+- \sqrt{1-4*1*(-2)} }{2} = \frac{-1+- \sqrt{9} }{2}= \frac{-1+-3}{2} [/tex]x₁=-2    x₂=1
Answer: x₁=-2    x₂=1


Apologiabiologyidn
x^2+x=2
first set to zero
x^2+x=2
subtract 2 from both sides
x^2+x-2=0
factor because if you have
x times y=0 then assume x and/or y=0 so

factor x^2+1x-2
to factor you find what 2 number add to 1 and multiply to get -2
the numbers are -1 and 2 so
it factors out to
(x-1)(x+2)=0
assume each is zero
x-1=0
add 1 to both sides
x=1

x+2=0
subtract 2 from both sides
x=-2

x=1 or -2
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