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A water balloon is catapulted into the air so that it's height, in meters, after t seconds is h = -4.9t^ +27t +2.4

How High is the balloon after 3 seconds?


Sagot :

[tex]h = -4..9t^2+27t+2.4\ for\ t=3[/tex]

Just replace t with 3 and solve.

[tex]h = -4.9*3^2 + 27*3 + 2.4 \\ h = -4.9*9 + 27*3 + 2.4 \\ h=-44.1 + 81 + 2.4 \\ \boxed{h=39.3}[/tex]