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How many moles of O2 are needed to react with 1.44 mol of Aluminum(Al)?
Show work please
Aluminum reacts with oxygen based on the following equation: 4Al + 3O2 → 2Al2O3
From this balanced equation, we can see that 4 moles of aluminum are required to react with 3 moles of oxygen.
So, to find the number of moles of oxygen needed to react with 1.44 moles of aluminum, all you have to do is cross multiplication as follows: required moles of oxygen = (1.44x3) / 4 = 1.08 moles
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