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Toni measured the height of her bedroom doorway with a measuring tape. She measured the height as 171 cm. The doorway’s actual height is 182.8 cm.

What is the percent error in Toni’s measurement? Round to the nearest tenth of a percent, if necessary.

A.
0.12%


B.
6.5%



C.
6.9%


D.
11.8%


Sagot :

First, subtract the two numbers.

[tex]\sf182.8-171=11.8[/tex]

Now divide this to the actual measurement.

[tex]\sf11.8\div182.8=0.0645514223[/tex]

Multiply by 100:

[tex]\sf0.0645514223\times100=6.45514223[/tex]

So the percent error is approximately [tex]\sf6.5\%[/tex]
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