Answered

IDNLearn.com: Where questions are met with accurate and insightful answers. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.

if a lawn measures 40 and 4/5 ft by 50 and 7/8ft how many square feet of seed will he need?

Sagot :

Apologiabiologyidn
so convert to improper fracitons (improper=x/y where x>y and the current one is mixed where it is in t s/f form) so

40 and 4/5=(40 times 5)/5 and 4/5=200/5 and 4/5=204/5

50 and 7/8=(50 times 8)/8 and 7/8=400/8 and 7/8=407/8

area=legnth times width
legnth =407/8
width=204/5
multiply 407/8 and 204/5

407/8 times 204/5=(407 times 204)/(8 times 5)=83028/40=2075.7 square feet

the answer is 2075.7 ft^2 of seed
Thompzacidn
To solve this just take 40 4/5*50 7/8=2075.7 so there would be about 2075.7 square feet of seed to plant.
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.