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Sagot :
Number of red cars = x
Number of white cars = y
x + y = 75
y + 3 = 2x
x + y = 75
y = 75 - x
(75 - x) + 3 = 2x
78 = 3x
26 = x
y + 3 = 2(26)
y + 3 = 52
y = 49
There are 49 white cars.
Number of white cars = y
x + y = 75
y + 3 = 2x
x + y = 75
y = 75 - x
(75 - x) + 3 = 2x
78 = 3x
26 = x
y + 3 = 2(26)
y + 3 = 52
y = 49
There are 49 white cars.
Answer: 51
Step-by-step explanation:
Let the number of red cars be r then the number of white cars is given by :-
[tex]2r+3[/tex]
Since, the total number of cars = 75
Therefore, we have
[tex]r+2r+3=75\\\\\Rightarrow\ 3r+3=75\\\\\Rightarrow3r=75-3\\\\\Rightarrow\ 3r=72\\\\\Rightarrow\ r=24[/tex]
Therefore, the number of red cars = 24.
and the number of white cars = 2(24)+3=48+3=51
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