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The base of an isosceles triangle is half the length of each of its congruent sides.
If the perimeter of the triangle is 120 inches, what is the length of the base?
120 = 1/2b + b + b 120 = 1/2b + 2b 120 = 2.5b ÷2.5 ÷2.5 48 = b <— that is the length of one of the congruent sides to find the base multiply by 1/2 and you get 24. THE ANSWER IS… B! :) hope i helped :)
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