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Sagot :
1). 5 t⁻¹ / [ (10t²) (3t⁰) ]
t⁻¹ means 1/t and t⁰ is ' 1 ', so the expression becomes
5 / [ t (10t²) (3) ] =
5 / [ 3t (10t²) ] =
5 / 30t³ =
1 / 6 t³ or (1/6) t⁻³
2). (2a) (6a²) / 4a³
Clear the parentheses in the numerator: 2a 6a² = 12a³
So the fraction becomes 12a³ / 4a³
Divide top and bottom by a³ : 12 / 4 = just 3 .
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