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(25^(-x+2))=((1/5)^x)

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Konrad509idn
[tex]25^{-x+2}=\left(\dfrac{1}{5}\right)^x\\ 5^{2(-x+2)}=5^{-x}\\ 2(-x+2)=-x\\ -2x+4=-x\\ x=4 [/tex]
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