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Jane has $10 more than Bill, Bill has $17 more than Tricia, and Tricia has $21 more than Steve. If the total amount of all their money is $135, how much money does each have?

Sagot :

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[tex]J \rightarrow Jane\\ B \rightarrow Bill\\ T \rightarrow Tricia\\ S \rightarrow Steve\\\\ J+B+T+S = 135\\\\ (10 + (17 + (21 + S) ) )+(17+(21+S))+(21+S)+S=135\\\\ 10 + 17 + 21 + S+17+21+S+21+S+S=135\\\\ 4S+107=135\\\\ 4S=135-107\\\\ S=\dfrac{28}{4}\\ \boxed{S=7}\\\\\ T=21+S\\ T=21+7\\ \boxed{T=28}\\\\ B=17+T\\ B=17+28\\ \boxed{B=45}\\\\ J=10+B\\ J=10+45\\ \boxed{J=55}[/tex]

[tex]55+45+28+7=135\\\\ \boxed{135=135}[/tex]

Jane has $55, Bill has $45, Tricia has $28, and Steve has $7.

Given that

Jane has $10 more than Bill, Bill has $17 more than Tricia, and Tricia has $21 more than Steve.

If the total amount of all their money is $135.

We have to determine

How much money does each have?

According to the question

Let the amount Steve be x,

The total amount Jane has is (10 +17+21+x)

The total amount Bill has is (17+21+x)

The total amount Tricia has is (21+x)

Then,

The total amount of all money = Jane money + Bill money + Tricia money + Steve money

[tex]\rm 135 =( 10+17+21+x)+ (17+21+x) + (21+x)+x\\\\135 = 48+x + 38+x+21+x+x\\\\135 = 4x+ 107\\\\4x = 135-107\\\\4x = 28\\\\ x = \dfrac{28}{4}\\\\ x= 7[/tex]

The Steve has $7.

Therefore,

The total money Jane has =  (10 +17+21+x) = 48 + 7 = $55

The total money Bill has = (17+21+x) = 38 +7 = $45

The total money Tricia has =  (21+x) = 21 +7 = $28

Hence, Jane has $55, Bill has $45, Tricia has $28, and Steve has $7.

To know more about Equation click the link given below.

https://brainly.com/question/14454996

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