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Which choice is equivalent to the quotient shown here when x>0
√72x^3 divided by √50x^2
a.6x/5
b.√22x
c.6√x/5
d.√72x^3 - 50x^2

Sagot :

Panoyinidn

[tex] {\sqrt{\frac{72x^{3}}{50x^{{2}}}} = \frac{\sqrt{72x^{3}}}{\sqrt{50x^{2}}} = \frac {\sqrt{36 * x^{2} * 2 * x}}{\sqrt{25 * x^{2} * 2}} = \frac{\sqrt{36}\sqrt{x^{2}}\sqrt{2}\sqrt{x}}{\sqrt{25}\sqrt{x^{2}}\sqrt{2}} = \frac{6x\sqrt{2x}}{5x\sqrt{2}} = 1\frac{1}{5}\sqrt{x} [/tex]

The answer is equal to C. [tex] \frac{6\sqrt{x}}{5} [/tex].

Ck247730idn

Answer to your question is C. 6 sqrt x / 5

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