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solve algebraically: the soccer field has an area of 6000 square yards. The field is 40 yards longer than its width. What are the dimensions of the field in years
lets width od field is x , x>0 (if x<0 it is no sense) yards and length is (x+40)yards So square of field is x(x+40)=6000 x²+40x=6000 x²+40x-6000=0 (x+100)(x-60)=0 x₁=-100 no sense x₂=60 yards - width of field x+40=x+60=100 yards - length of field Answer: 60 yards - width of field, 100 yards - length of field
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