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Can anyone tell me how to graph 7x+y=5

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You have the equation 7x+y=5
But you must rearrange this into y=mx+b form
to do this subtract 7x from both sides

y= -7x+5

On the y axis plot a dot on 5 because that is the y intercept. 

To find the x intercept let y=0
 0= -7x+5
1. Subtract 5 to both sides
-5=-7x
2. Divide by -7 to both sides
x= -5/-7
x=5/7 
The x intercept is 5/7, so on the x axis mark a dot on 5/7 which is approximately at 0.7
Once you have marked one dot on the y axis at 5 and another dot on the x-axis at 0.7 then you draw a straight line through these points and you have graphed the function 7x+y=5 
To graph an equation, you first need to solve it for y. This means turning the equation into this form: Y=.......

For your equation, once you solve it for Y, you get this:

[tex]y = -7x +5[/tex]

Now, the coefficient of X is a very crucial part of graphing an equation. Once the equation is solved for Y, the coefficient of X is going to be the slope of the line you are graphing. The slope of a line is how much Y goes up every time X is increased by 1.

To graph an equation, you need to put in a number for X and find the matching value for Y and then graph that point. To do this, you will need a coordinate plane. I can't show you what that looks like on here. But, I will do my best to explain how it is done.

Now, for your equation:

[tex]y = -7x +5[/tex]

Simply chose a number for X and find the matching value for Y. I'll try 0 for an example:

[tex]y = -7(0) +5[/tex]

-7 * 0 is 0. Therefore, your new equation looks like this:

[tex]y =+5[/tex]

Therefore, one "Solution pair" to this equation is (X=0,Y=5)

Simply repeat this process and plot the solution pairs on the coordinate plane and then connect the dots.
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