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The product of some negative number and 13 less than three times that number is 10. Find the number.
The equation would look like this: 3y - (y×13) = 10 To solve this, we need to be able to get y by itself. First, put together the 13 and y in the parentheses. 3y - (y×13) = 10 3y - 13y = 10 Next, subtract the 13y from the 3y 3y - 13y = 10 -10y = 10 Finally, divide by -10 to find what y is equal to. -10y = 10 -10y ÷ -10 = 10 ÷ -10 y = -1 The number you are looking for is -1
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