Giannamcghee1999idn
Answered

From science to arts, IDNLearn.com has the answers to all your questions. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.

multiply or divide and then simplify

(x+1)^2/(x-5)*(x-3)/(x+1)

3x+3/2 divided by 4/9x+9

4a/3a-3*3(a-1)/16a

x+2/x-1 divided by 5x+10/x-2

Sagot :

[tex]\frac{(x+1)^2}{x-5}\cdot\frac{x-3}{x+1}=\frac{x+1}{x-5}\cdot\frac{x-3}{1}=\frac{(x+1)(x-3)}{x-5}=\frac{x^2-3x+x-3}{x-5}=\frac{x^2-2x-3}{x-5}\\\\D:x\neq5\ \wedge\ x\neq-1[/tex]


[tex]\frac{3x+3}{2}:\frac{4}{9x+9}=\frac{3x+3}{2}\cdot\frac{9x+9}{4}=\frac{27x^2+27x+27x+27}{8}=\frac{27x^2+54x+27}{8}\\\\D:x\neq1[/tex]


[tex]\frac{4a}{3a-3}\cdot\frac{3(a-1)}{16a}=\frac{1}{3a-3}\cdot\frac{3a-3}{4a}=\frac{1}{4a}\\\\D:a\neq1\ \wedge\ a\neq0[/tex]


[tex]\frac{x+2}{x-1}:\frac{5x+10}{x-2}=\frac{x+2}{x-1}\cdot\frac{x-2}{5x+10}=\frac{x+2}{x-1}\cdot\frac{x-2}{5(x+2)}=\frac{1}{x-1}\cdot\frac{x-2}{5}=\frac{x-2}{5x-5}\\\\D:x\neq1\ \wedge\ x\neq2\ \wedge\ x\neq-2[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.