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Elimination method
4x-2y=48
2x+6y=-18

Sagot :

[tex]4x-2y=48\\ \\ 2x+6y=-18[/tex]

First we'll multiply the second equation by -2


[tex]-2\cdot (2x+6y)=-2\cdot -18\\ \\ -4x-12y=36[/tex]

Now let's add the new equation and the first one.

[tex](4x-2y)+(-4x-12y)=48+36\\ \\ 4x-4x-2y-12y=48+36\\ \\ -14y=84\\ \\ y=\frac { 84 }{ -14 } \\ \\ y=-6[/tex]

We found y's value. We'll plug it in one of the equations to find x's value.

[tex]y=-6\\ \\ 4x-2y=48\\ \\ 4x-2\cdot -6=48\\ \\ 4x+12=48\\ \\ 4x=48-12\\ \\ 4x=36\\ \\ x=\frac { 36 }{ 4 } \\ \\ x=9[/tex]

Solution ;

(9, -6)


Panoyinidn
4x -  2y =  48 ⇒ 4x -    2y = 48
2x + 6y = -18 ⇒ 4x + 12y = -36
                                 -14y = 84
                                  -14    -14
                                       y = -6
                          4x - 2(-6) = 48
                            4x + 12 = 48
                                  - 12 - 12
                                    4x = 36
                                     4      4
                                      x = 9
                                (x, y) = (9, -6)
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