Join IDNLearn.com and become part of a knowledge-sharing community that thrives on curiosity. Get step-by-step guidance for all your technical questions from our knowledgeable community members.
Sagot :
The center is at the origin and the point [tex](3,0)[/tex] lies on the circle, so [tex]r=3[/tex]
[tex]A=\pi r^2\\ A=\pi \cdot3^2\\ A=9\pi\\ A\approx28.27[/tex]
[tex]A=\pi r^2\\ A=\pi \cdot3^2\\ A=9\pi\\ A\approx28.27[/tex]
we know that
the equation of a circle with the center at the origin is equal to
[tex] x^{2} +y^{2} =r^{2} [/tex]
step 1
with the point (3,0) find the value of the radius
substitute the values of
[tex] x=3\\ y=0 [/tex]
in the equation of the circle above
so
[tex] 3^{2} +0^{2} =r^{2} [/tex]
[tex] 3^{2} =r^{2} [/tex]
[tex] r =3 [/tex]
step 2
with the radius find the area of the circle
area of the circle is equal to
[tex] A=\pi *r^{2} [/tex]
for [tex] r=3 [/tex]
[tex] A=\pi *3^{2} [/tex]
[tex] A=28.27 [/tex]units²
therefore
the answer is
the area of the circle to the nearest hundredth is [tex] A=28.27 [/tex]units²
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.