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Point P lies on the line with the equation y-4=3(x-2). If the x-coordinate of P is 4, what is the y-coordinate of P

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Let's start by tidying up that equation and put it into slope-intercept form (y = mx + b); from there, we can plug in coordinates.

[tex]y - 4 = 3(x-2)[/tex]

Let's use the distributive property on the right side:
[tex]y - 4= 3x - 6[/tex]

Now add 4 to both sides
[tex](y - 4) + 4 = (3x - 6) + 4[/tex]

Which simplifies to:
[tex]y = 3x - 2[/tex]

Since that's the equation of our line, now we can plug in coordinates and see what it churns out. 

We know that the x-coordinate of P = 4 so let's substitute 4 in for x and calculate the y-coordinate:

[tex]y = 3(4) - 2[/tex]
[tex]y = 12 - 2[/tex]
[tex]y = 10[/tex]

So the y-coordinate for point P = 10
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