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If g(x) = [tex] \sqrt{x-7} [/tex] , find g(8), g(32) and g(80).

Sagot :

Apologiabiologyidn
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g(x)=[tex] \sqrt{x-7} [/tex]


this means if you put in 8 for x then you will get g(8)=[tex] \sqrt{8-7}= \sqrt{1}=1 [/tex]

so subsitute and solve

g(8)=[tex] \sqrt{8-7}= \sqrt{1}=1  or -1 [/tex]


g(32)=[tex] \sqrt{32-7}= \sqrt{25}=5 or -5 [/tex]


g(80)=[tex] \sqrt{80-7}= \sqrt{73}=[/tex] aprox 8.544  but √73 would be acceptable

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