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Find the value of b that makes [tex] x^{2} +bx+\frac{9}{4} [/tex] a perfect square trinomial

Sagot :

Apologiabiologyidn
perfect square trinomial is like

(x+4)^2=x^2+8x+16
they are represented as such
ax^2+bx+c
so to solve for b you do
(√c) times 2=b so

c=9/4
square root=3/2 because 3/2 times 3/2=9/4
(√(9/4)) times 2=(3/2) times 2=6/2=3
so b=3

x^2+3x+(9/4)
if factored, it gives
(x+(3/2))(x+(3/2))  or
(x-(3/2))(x-(3/2))


if this equation is equal to 0 then x=-3/2 or 3/2

the value is 3
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